The consideration of a basic case of a stagnant fluid first takes place, where only weight and pressure forces are significant. Therefore, one must know these quantities so as to determine a particular liquid’s hydrostatic pressure. Furthermore, the main factors which influence it are the liquid’s density and the local gravity. The liquid’s hydrostatic properties are not constant. Furthermore, the height of a liquid column, of uniform density, is such that it turns out to be directly proportional to the hydrostatic pressure. Hydrostatic pressure refers to the pressure whose generation takes place by the weight of liquid above a measurement point when the liquid is in a state of rest. So our force becomes 62.4 and then we need to figure out how to find the area of that layer.2 FAQs on Hydrostatic Pressure Introduction to Hydrostatic Pressure So we have square feet times feet and if we divide that by cubic feet, that would cancel out our feet units and we're going to lift with pounds, which is what our force is going to be measured in. We would need to multiply that by the area of that layer right there, which should be measured in square feet, and then we would need to multiply that by the depth of that which is y and that we measured in feet. So the tank is bounded by these curves, so this thing is filled with water, so we're just going to take a very thin layer of water here and we're gonna, let the thickness of that thickness of that be delta y, okay and then it's going to be At a depth of y units, that's gonna be the depth of that layer of water, so the hydrostatic force of the water on that plate just on this thin layer would be the weight density of water, which is 62.4 pounds per cubic foot. That'S y equals 3 times of natural log of 17 point okay. That'S just the x axis, and then we have this constant flat line. This on the left side would be y equals 3 times the natural log of negative x, and we got y equals 0. This curve here will be y equals 3 times the natural log of x. Has a density of 62.4 per cubic foot, so we have this taint shaped like this bounded by these curves. Find the hydrostatic force on the flat vertical side of a tank that has the shape of the region bounded by y equals 0 y equals 3 l n x y equals 3 l n of negative x and y equals 3 l n of 17 point water.
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